Question

Find the solutions to the equation in the interval $0 \le t \le \pi$. Enter your answers as a comma-separated list. $(\cos t - 3)(2\sin^2 t - 1) = 0$ t =

          Find the solutions to the equation in the interval $0 \le t \le \pi$. Enter your answers as a comma-separated list.
$(\cos t - 3)(2\sin^2 t - 1) = 0$
t =

Find the solutions to the equation in the interval 0 ≤ t ≤π. Enter your answers as a comma-separated list.
(cos t - 3)(2sin^2 t - 1) = 0
t =

Added by Bryan W.

Precalculus with Limits

Ron Larson 2nd Edition

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Find the solutions to the equation in the interval 0<=t<=π. Enter your answers as a comma-separated list. (cos(t)-3)(2sin^2(t)-1)=0 t= Find the solutions to the equation in the interval 0<=t<=π. Enter your answers as a comma-separated list. cos(t)32sint0