Question

Find the values of the trigonometric functions of \theta from the information given. $\sin(\theta) = -\frac{12}{13}$, $\theta$ in Quadrant IV $\cos(\theta) = $ $\tan(\theta) = $ $\csc(\theta) = $ $\sec(\theta) = $ $\cot(\theta) = $

          Find the values of the trigonometric functions of \theta from the information given.
$\sin(\theta) = -\frac{12}{13}$, $\theta$ in Quadrant IV
$\cos(\theta) = $
$\tan(\theta) = $
$\csc(\theta) = $
$\sec(\theta) = $
$\cot(\theta) = $
        
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Find the values of the trigonometric functions of θfrom the information given.
sin(θ) = -(12)/(13), θ in Quadrant IV
cos(θ) =
tan(θ) =
csc(θ) =
sec(θ) =
cot(θ) =

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Find the values of the trigonometric functions of heta from the information given. cos( heta )=(3)/(17),sin( heta )<0 sin( heta )= tan( heta )= csc( heta )= sec( heta )= cot( heta )=Find the values of the trigonometric functions of heta from the information given. sin( heta )=-(12)/(13), heta in Quadrant IV cos( heta )= tan( heta )= csc( heta )= sec( heta )= cot( heta )= Find the values of the trigonometric functions of e from the information given. e in Quadrant IV 13 cos(0) tan(0) csc(0) sec() cot(0) =
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Transcript

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00:01 We're given tangent theta equals to four -thirds.
00:05 And we're looking at a quadrant three angle.
00:08 So i'm going to get my quadrant three angle.
00:11 Here we go.
00:12 Tangent is four -thirds, so that means we're looking at opposite over adjacent.
00:17 But since we're dealing with quadrant three, that has to be a negative four and a negative three.
00:22 So notice if i put negative four over negative three, i'm going to get positive four over three.
00:28 So i now know that this is going to be pythagorean triple, so my hypotenuse has to be five.
00:35 So what do we want to know? we want to know all of the function values...
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