00:01
Given that correlation, for the given set of data, correlation are equal to 0 .885 and a regression equation is also given, which is given as y hat is equal to 38 .86 plus 2 .24 x, where it is mentioned x equal to 3rds per second and y is the 10 .8.
00:31
In fahrenheit.
00:34
Now for the part a, it is asked when the third second is 19, what will be the predicted temperature according to the given expression.
00:48
So it is evaluated by substituting x in the given regression equation.
00:53
So for the x value, here we have asked you to find when it is 19, we have to calculate the predicted temperature.
01:01
So on calculation, this predicted temperature is 8 .1 .4 fahrenheit.
01:08
Now, again, it is asked when x equal to 27, what will be the predicted temperature? so we can again substitute instead of x 27, so which is 38 .86 plus 2 .24 into 27...