For a population data set, \(\sigma = 17.20\). a. What should the sample size be for a 98\% confidence interval for \(\mu\) to have a margin of error of estimate equal to 6.80? n = b. What should the sample size be for a 95\% confidence interval for \(\mu\) to have a margin of error of estimate equal to 4.76? n =
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Step 1: The formula for the margin of error is: $$E = z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$$ where: * $E$ is the margin of error * $z_{\alpha/2}$ is the critical value for the given confidence level * $\sigma$ is the population standard deviation * $n$ is the Show more…
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