For natural number m and n, $(m \times n^{++}) = (m \times n) + 1$ True False
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Here, $n^{++}$ means $n+2$. So the equation becomes: $m \times (n+2) = (m \times n) + 1$ $mn + 2m = mn + 1$ $2m = 1$ $m = \frac{1}{2}$ Show more…
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