00:01
In this question, it is given that integration 1 to 4 f x d x is equals to 5, integration 3 to 4 fx d x is equal to 7 and integration 1 to 8 fx d x is equals to 11.
00:27
We are required to find the value of integration 4 to 8 fx dx, integration 4 to 3 fx dx, integration 1 to 3 fx dx integration 1 to 3xxx integration 8 to 8 to 4, fx dx and integration 4 to 4 fx d x.
01:17
So let's see how to solve this question.
01:21
We know that the integration a to c fx dx plus integration c to b fx d x dx is equal to integration a to b fx dx dx so based on this theorem, we can write integration 4 to 8 fx dx is equals to integration 4 to 1 fx dx plus integration 1 to 8 fx dx and we can write it as minus integration 1 to 4x dx plus fx dx plus and we can write it as minus integration 1 to 4 fx dx plus integration 1 to 8 f x d x now substitute all the values so we have the value of integration 1 to 4 f x d x that is 5 plus we have the value of integration 1 to 8 f x d x that is 11 so when we further calculate this finally we get integration 4 to 8 f x d x is equals to 6 so this is the final answer for part a and now let's move to part b.
03:06
The integration 4 to 3 fx dx will be equals to minus of integration 3 to 4 fx d x we have the value of integration 3 to 4 fx d x.
03:22
We have the value of integration 3 to 4 fx d x so substitute this so finally we get integration 4 to 3 fx d x is equal to minus seven so this is the final answer for part b and now let's move to part c the integration of one two three f x d x will be equals to integration one to four f x d x d x plus integration four to three fx d x d x and we can write it as integration 1 to 4 f x d x minus of integration 3 to 4 f x d x we already have the value of these integrals so now substitute those values so we will have integration 1 2 3 f x d x is equal to 5 minus 7 so this will be equals to minus 2 so this is the final answer for part c and now let's move to part d.
04:55
The integration of 3 to 8 fx d x can be written as integration 3 to 4 f x dx plus integration 4 to 1 fx dx plus integration 1 to 1 8 fx d x now substitute the value of these integrals so we can write 7 minus 5 plus 11...