00:01
For task 1 through 8 considering the following data.
00:05
So we're given a list of values using the list of 17 numbers, the median of this data.
00:12
So the middle is 2 .8.
00:16
If you find the median using the original method, you have to arrange the values in numeric order first.
00:21
That is true.
00:24
The interquartile range for this data is 6 .55.
00:33
The formula for calculating the interquotile range is quartile 3 minus quartile 1.
00:41
Number five, using techniques we've studied in this course, the upper and lower cutoff points, round of three decimal places for identifying outliers.
00:49
In this given data sample are negative 9 .625 and 16 .575.
00:58
So to find that, remember, we take our intercortile range and we multiply at times 1 .5.
01:04
And then we take quartile one and we subtract that and we take quartile three and we add that.
01:20
Anything that's outside of that range would be considered an outlier.
01:25
Number six, the summary command shows a list of outliers if there are any.
01:31
That is false.
01:34
Seven, the list of outlier values is 18.
01:39
Would be an outlier.
01:42
And number eight, the standard deviation of the list of 17 numbers is 5 .249...