00:01
The specific weight of the oil is given as, let's find as 0 .75 m into g, right? so, let's convert 9180 newton per meter.
00:12
So, we will get as 7357 .5 newton per meter.
00:20
Similarly, let's find the area which will be equal to, area let's find as 1 .2 into 1 .8 which is equal to 2 .16 meter square.
00:32
Now the location of center of gravity of the right side that is that's written down as y1 dash will be equal to 1 .8 by 2 which will be 0 .9 meters.
00:45
Now force of ab at the right side right that is let's find force on oil equal to let's say this this is equal to specific weight of oil into area into y1 bar.
01:03
So, we have all the values with the substituting.
01:06
We will get the forces 14302 .98 newtons.
01:12
So, point of application of f oil.
01:15
Oil point of application of the force on oil will be equal to 2 by third of 1 by 1 .8 which will be equal to 1 .2 meters from the point...