The one-to-one functions $g$ and $h$ are defined as follows. $g = \{(0, 3), (1, 4), (2, -1), (3, 8), (8, 9)\}$ $h(x) = 3x - 4$ Find the following. $g^{-1}(3) =$ $h^{-1}(x) =$ $(h \circ h^{-1})(2) = $
Added by Jacob B.
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Step 1: To find g^{-1}(3), we need to find the x-value in the set g that corresponds to the y-value 3. Show more…
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