00:01
This problem asks if danica has $1 ,200 to invest at 8 % per year compounded monthly, how long will it be before he has $2 ,400 if compounding is continuous, how long will it be? so we have the two formulas that we need listed here.
00:13
The first we'll use for compounded monthly, so he wants to know how long it will take for the y value, the final amount, to be $2 ,400, equal to the initial amount, which is $1 ,000, times 1 plus the rate, which was 8%, and it's compounded monthly, so our end value is 12, raised to the 12 value for n again times t so t is what we're trying to solve for so it's a solve for a variable in exponent we have to isolate the base so this one plus 0 .08 divided by 12 we need to get by itself so we'll divide 1200 over and 1200 divided into 2 so we're left with 2 equal to the 1 plus 0 .08 divided by 12 race to the 12 t now we'll use logarithms and i'm going to use natural log and that gives us the ability to take the exponent right as a coefficient.
01:00
So i'm going to do natural log of both sides and that's going to let us move this 12t in front of this natural log.
01:06
So 12t times natural log of 1 plus 0 .08 divided by 12 and that's equal to natural log of 2.
01:14
So if we're solving for t, we're going to divide by the entire 12 natural log 1 plus 0 .08 divided by 12 on both sides.
01:22
So natural log of 12 divided by the same thing.
01:24
12 times natural log 1 plus 0 .08 divided by 12.
01:29
And that's going to give us our t value.
01:31
And our t value for the first part of the problem is 8 .693.
01:38
So looking at our choices, it looks like b is the only choice that could be correct.
01:42
But we'll make sure that this is correct by working out the second part of the problem too.
01:46
The second part says if it's compounded continuously, how long will it take to reach the 2400? so same thing...