Question

A Air 40 m B Air oil water 37 m 35 m C D 

          A
Air
40 m
B
Air
oil
water
37 m
35 m
C
D
A Air 40 m B Air oil water 37 m 35 m C D

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Gauge pressure measured in tank A is 20 kN/m2 and in tank B is -29 kN/m2. The water surface is at an elevation of 37 m, the oil surface is at an elevation of 40 m, and the oil-manometer liquid interface (point C) is at an elevation of 35 m. The specific gravity of the oil is 0.8, and the specific gravity of the manometer liquid is 1.6. (The density of water can be considered as 1000 kg/m3) So, determine the elevation of point D.
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Transcript

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00:01 In this problem, given data is, that is, atmospheric pressure, p atmosphere is equal to 85 .6 kilo -pascal and it becomes 8560 pascal.
00:25 And the density of water that is row w is is thousand kg per meter cube density of oil is equal to row 0 850 kg per meter cube and density of mercury that is row and is equal to 1360 kg per meter cube and the height will be of water column h1 is given as that is 0 .2 meter and height of oil column from water level that is h2 meter that is h2 and height of mercury column that is h3 is equal to 0 .35 meter.
01:59 From diagram we can use the data as, that is, pressure at point b, it becomes pb is equal to pressure of air plus row, row, o that is oil, density of oil g h1 plus row water g h2 this is the first equation now it will be the pressure from the left side it is and now the pressure at point b from right side then we can write pv is equal to atmosphere pressure plus ro m g h 3 this is step second and from both the steps from one and two we can write it as p atmosphere plus row m g h 3 is equal to p air plus row o g h1 plus row w g h 2 now this can be written as p air is equal to p atmosphere plus ro m g h 3 minus row g h 1 minus row w g h 2 this is the third step third equation now we know row m g h 3 is equal to 136 0 by putting values we can solve this and it is equal to 46648 pascal now row o g h1 will be 850 into 9 .8 into 0 .1 which is equal to 833 pascal and row w g h2 is equal to thousand into 9 .8 into 0 .2 is equal to 1960 pascal.
04:49 Now, by putting in equation three, putting in equation three, it becomes p .a .r...
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