First, we can factor out a sin(x) from the equation:
sin(x)(2sin(x) + \sqrt{3}) = 0
Now, we have two possible cases for the equation to be true:
1) sin(x) = 0
2) 2sin(x) + \sqrt{3} = 0
For case 1, we know that sin(x) = 0 when x = n\pi, where n is an integer.
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