00:01
Hello students, let's solve this question here.
00:03
It is given that the pressure angle phi is equal to 20 degree, the power transmitted p is equal to 10, rotation speed n is equal to 1750 rpm, the module m is equal to 2 mm, teeth on the pinion i .e.
00:26
T is equal to 18, the teeth on the gear i .e.
00:30
T is equal to 85 and the phase width b is equal to 32 micrometer.
00:37
Now let's calculate the allowable contact number.
00:40
For that the equation is sigma h is equal to 2 .35 into hb plus 165 .86 where hb is a brainial hardness number and its value is 590 for a a11 material.
01:03
Let's substitute and find out sigma h.
01:05
It will be 2 .35 into 590 plus 165 .86.
01:13
On solving we will get sigma h is equal to 1552 .3 mpa.
01:22
Now let's calculate the hardness ratio factor where the equation is zw is equal to 1 plus b into t divided by t minus 1...