Given: AB || CD, BC || AD, BD ∩ AC = O, M ∈ BC; N ∈ AD Prove: BM = ND BD and AC are diagonals MN goes through the center, which is also where BD and AC bisect and point O Can you guys put the answer? It would be a big help. Thanks (:
Added by Dennis R.
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Since AB ∥ CD and BC ∥ AD, we have ∆ABC ∼ ∆ADC by AA similarity. Show more…
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