00:01
Here i have to draw the structures of each formula according to its iopac name.
00:07
Let's do this.
00:08
So the first one is 1 .1 .1.
00:15
Dimitil, butyl.
00:23
2.
00:24
Ethoxy.
00:27
1 .2 .3.
00:33
Trinitra cyclobutane.
00:43
Okay.
00:45
So here that is important that it's cyclobalbutane.
00:48
Butane.
00:49
Let's show cyclobutane.
00:53
So it means that i have to show the four member cycle.
00:59
And now let's show the substitutes.
01:01
So let's label carbons.
01:03
One, two, three, four.
01:09
And now let's start with the second one.
01:13
So each instance is just a toxin.
01:20
Then that is one, two, three, three nitro cyclobutane.
01:34
And there are also two substitutes.
01:37
Which are 1 -1.
01:41
There is also substituted at the first carbon, that is 1 -1 -dimetil butyl.
01:47
Here i have to draw the structure.
01:50
It means that i need to show 4 carbons, 1, 2, 3, 4.
01:55
And now i'm going to show 2 metal groups at the 1st carbon of the substituting.
02:01
So that is the answer to the first question.
02:04
That's the first molecule.
02:07
Let's label this number one.
02:10
And now let's move on to the next one, which is 1 -24 tricyclopropyl.
02:26
1 -22 dichloropentyl.
02:36
Cyclohexane.
02:40
Now let's start with the cyclohexane unit.
02:50
Here i have to draw the structure...