Question

Given $\log_b (2) = x$ and $\log_b (3) = y$. Find the following logarithms in terms of the $x$ and $y$. 1 $\log_b (144) =$ 2$\log_b (0.75) =$ 3 $\log_b (\sqrt{6b^{-5}}) =$ 4$\log_6 (9b) =$ Note: To input expressions like 5x input 5x not x5 (this is to save computer answer checking time). Similarly, to input $x + y - 4$, type $x + y - 4$ but not $-4 + x + y$ or $x - 4 + y$ (meaning constants comes after variables addition/subtraction). This is to save computer answer checking time. To input $\frac{x + y}{2}$ type $(x + y)/2$. Typing $x + y/2$ is incorrect as this is equal to $x + \frac{y}{2}$ not $\frac{x + y}{2}$. Therefore, make use of parentheses appropriately.

          Given $\log_b (2) = x$ and $\log_b (3) = y$. Find the following logarithms in terms of the $x$ and $y$.
1 $\log_b (144) =$
2$\log_b (0.75) =$
3 $\log_b (\sqrt{6b^{-5}}) =$
4$\log_6 (9b) =$
Note:
To input expressions like 5x input 5x not x5 (this is to save computer answer checking time). Similarly, to input $x + y - 4$, type $x + y - 4$ but not
$-4 + x + y$ or $x - 4 + y$ (meaning constants comes after variables addition/subtraction). This is to save computer answer checking time.
To input $\frac{x + y}{2}$ type $(x + y)/2$. Typing $x + y/2$ is incorrect as this is equal to $x + \frac{y}{2}$ not $\frac{x + y}{2}$. Therefore, make use of parentheses appropriately.

Given (2) = x and (3) = y. Find the following logarithms in terms of the x and y.
1 (144) =
2(0.75) =
3 (√(6b^-5)) =
4log6 (9b) =
Note:
To input expressions like 5x input 5x not x5 (this is to save computer answer checking time). Similarly, to input x + y - 4, type x + y - 4 but not
-4 + x + y or x - 4 + y (meaning constants comes after variables addition/subtraction). This is to save computer answer checking time.
To input (x + y)/(2) type (x + y)/2. Typing x + y/2 is incorrect as this is equal to x + (y)/(2) not (x + y)/(2). Therefore, make use of parentheses appropriately.

Added by Charles W.

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