Question

Given $P(x) = -2x^4 - x^3 + x + 2$, using the Upper and Lower Bounds Theorem to show that the real zeros of $P(x)$ lie between $-2$ and $1$ we get

Name: Given P(x) = -2x^4 - x^3 + x + 2, using the Upper and Lower Bounds Theorem to show that the real zeros of P(x) lie between -2 and 1 we get
Uploaded: 2021-12-11T21:00:57-08:00
Duration: 22 s
Channel: James Kiss
Description: Given P(x) = -2x^4 - x^3 + x + 2, using the Upper and Lower Bounds Theorem to show that the real zeros of P(x) lie between -2 and 1 we get

          Given $P(x) = -2x^4 - x^3 + x + 2$, using the Upper and Lower Bounds Theorem to show that the real zeros of $P(x)$ lie between $-2$ and $1$ we get

Added by Tanya M.

Precalculus with Limits

Ron Larson 2nd Edition

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Given P(x) = 2x^4 - x^3 + x + 2, using the Upper and Lower Bounds Theorem to show that the real zero of P(z) is between -2 and 1. Given P(x) = 2x^4 - x^3 + x + 2, using the Upper and Lower Bounds Theorem to show that the real zero of P(z) is between -2 and -1.