Given that CF is a tangent to the circle shown aCF=6.AC=12.BC= bAG=3.BE=10.BG=4.DG= cAC=12,BC=4,DC=3,CE= dAG=8.GD=5,BG=10,GE= eCF=6.AB=5.BC= fEG=4,GB=2,AD=9,GD= gAC=30,BC=3,CD=ED,ED= hAC=9.BC=5.ED=12.CD= iED=8.DC=4,FC= jFC=6,ED=9,CD=
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Using the tangent-secant theorem, we have AC^2 = AB * AD, so 12^2 = 5 * AD, which gives us AD = 24/5. Show more…
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