5. Given that sin( heta) = -frac{5}{13} and that heta is in Quadrant III with frac{5pi}{4} < heta < frac{3pi}{2}, find the exact value of cos(2 heta).
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So, we have $0 \cdot \cos(20) = 0$. Now, we need to find the exact value of $\sin(180 - 20)$. We know that $\sin(180 - x) = \sin(x)$, so we have $\sin(180 - 20) = \sin(20)$. Show more…
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