Given triangle ABC, AD bisects angle BAC, and AE = ED.
Prove AE/AC = BD/BC.
Because I can't draw it, I will explain. It's a triangle, A is the point at the top, B is the point at the bottom left, and C is the point at the bottom right. There is a line going right down the middle, which is point D. So point D is between point B and C. From point D, there is a short line which goes to the middle of points A and C. This point is E.