Got wrong ols hell 3 a physicist plays a game of pool...

Name: got wrong ols hell 3 a physicist plays a game of pool billiards which involves hitting the wall at an angle of 25 to the wall after the collision the ball leaves the wall at the same angle o 52122
Uploaded: 2022-05-13T08:12:48-08:00
Duration: 3 min 21 s
Channel: Kritika Mishra
Description: got wrong ols hell 3 a physicist plays a game of pool billiards which involves hitting the wall at an angle of 25 to the wall after the collision the ball leaves the wall at the same angle o 52122

got wrong ols hell 3. A physicist plays a game of pool billiards which involves hitting the wall at an angle of 25 to the wall. After the collision, the ball leaves the wall at the same angle of 25. bounces off the wall? [1 pt] a If the collision is elastic, what is the speed of the ball after it m=16Sg mvcos=o VF1.2m1S 8=25 (b What is the impulse delivered by the wall, still assuming the collision is elastic? [2 pt] P=mvCoso P=16S12coS P=179.45.Kg.mK (c During the initial hit if the pool cue m=0.5 kg transferred all of its momentum to the ball, what was the velocity of the pool cue when it hit the ball? [2 pt] mV+mV2miV,4mV m=165gV=1.2m3 WT m=OSegV= miVi+mz 118.5 mv+m 151.2+05 1.2+05 V=0.91m1s mv+my(m+mV

Transcript

00:01 Question we are given that this is a cube ball a given initial velocity 5 meter per second this one was resting right after the collision this wall has a speed of 4 .5 meter per second and speed for this one is not known so option of restriction is 0 .8 given to us as we know coefficient of restriction is what we hostee of separation divided by velocity of approach over here this must be able to e over here this low state of approach is 5 minus 0 and velocity of separation is so this is velocity of approach let me rewrite it velocity of separation is let us say this is coming in this direction 4 .5 minus v and velocity of approach is 5 minus 0 this must be 0 .8 so this velocity would be 0 .5 per second also we can calculate it using another equation that can be conservation of linear momentum so m into 5 plus 0 much equal to m into v plus m into 4 .5 from here also this am will this velocity will come out to be 0 .5 meter per second all right now in the second part it says that now it makes an again a collision with the cousin c at position c right so this was moving at an angle of 30 degree initially so this angle was 30 degree right so if we take two component of this velocity this one would be 4 .5 sine 30 and this is 4 .5 force 30 degree so this this perpendicular to the whole component will be only affected this parallel component will remain same right so what will happen with this so this is velocity of approach 4 .5 post 30.

02:18 Velocity of separation will be over here.

02:21 So this must be equal to 0 .6.

02:23 So velocity of separation would be equal to 4 .5 into 0 .6.

02:31 Post 30.

02:38 So this is 2 .33 meter per second.

02:42 Now our ball would be moving with 2 .33 meter per second in this direction and 4 .5 by 2 that means 2 .25 meter per second in this direction...