00:01
The question is ammonia and oxygen react to 4 nitrogen and water.
00:05
So first question is that how many gram of o2 are needed to react with the 8 mole of nh3? so reaction is given 4 ns 3 plus o2.
00:23
It gives 2 mol of n2 plus 6 mole of h2.
00:28
In the question we have mole of ns3, that is the 8.
00:33
Now from the structure metric from the mole ratio we can calculate mole of o2.
00:43
4 mool ns3 gives 8 more o2.
00:46
8 mol and s3 will give 6 mole o2.
00:55
So mass of o2 will be more.
00:58
Mass of o2 will be mole into molar mass.
01:05
So mole is the 6, mular mass that will come out here, 192.
01:13
Right for the second part in the second part is how many gram of n2 can be produced when 6 .5 gram of o2 reacts so in the question we have weight of o2 is the 6 .5 gram so first we have to calculate mole of o2 for the applying stereometric ratio so mole is mass by molar mass 6 .5 divided by 32 gram per mole that will come out here 0 .2 more of 2.
01:52
Now mole of n2 will be what? that is the 0 .2 into 4 divided by 3 from the stochometry copy shape.
02:03
It will be equal to 0 .26 mold.
02:07
So w upon n2 mass of n2 will be more into molar mass...