How many ATOMS of nitrogen are present in 4.41 grams of dinitrogen tetroxide, N2O4? How many GRAMS of oxygen are present in 1.06×10^23 molecules of dinitrogen tetroxide?
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41 grams of dinitrogen tetroxide, N2O4. Given: - Mass of N2O4 = 4.41 g - Molar mass of N2O4 = 92.02 g/mol - Number of nitrogen atoms in one molecule of N2O4 = 2 Number of moles of N2O4 = Mass / Molar mass Number of moles = 4.41 g / 92.02 g/mol ≈ 0.048 mol Number Show more…
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