00:02
Calcemahydroxide reacts with phosphoric acid to form calcium phosphate and water.
00:29
This is an unbalanced chemical equation, so let us go ahead and get this balanced.
00:37
Looks like i will need a three here and a two here.
00:43
That would give me six.
00:47
Six, probably a six there.
00:51
Excuse that six.
00:51
Now i have three calisiums, three calcums.
00:53
I have two phosphates and two phosphates.
00:58
I have two times three, six o's and six o's, twelve h's, and six and six.
01:03
Okay, so my coefficients are three, two, one, and six.
01:08
How many grams of phosphoric acid are needed to react completely with 34 .6 grams of calcium hydroxide? and then we're asked how much of this could be produced.
01:38
Okay, so i don't have any limiting.
01:40
So i'm going to start with 34 .6 grams of calcium hydroxide.
01:51
And i'm going to go get my molar mass of this.
01:58
Calcium oh2.
02:00
Calcium hydroxide is 74 .09.
02:14
And both of these are calcium hydroxide.
02:24
Next, i'm going to do this one first.
02:26
So i'm going to put my moles of h3, p .o4, and moles.
02:33
Of calcium hydroxide, and i've got a 3 and a 2, and i'll let me verify that this asked me for grams, grams of phosphoric acid.
02:51
So now i'm going to go find the molar mass of h3p -o -4, which will be 97 .99 grams of h3, p .04, or i made it, per mole of h3, p -04.
03:17
I'm going to put these into my calculator now...