How much heat is needed to warm 250 g of water (about 1 cup) from 22 °C (about room temperature) to near its boiling point, 98 °C? The specific heat of water is 4.18 J/g-K ____ kJ (Give your answer as a numeric only. Do not include units.) QUESTION 9 Based upon your answer in the above question: What is the molar heat capacity of water? ____ J/mol-K (Give your answer as a numeric only. Do not include units.)
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We can use the formula for heat transfer: Q = mcΔT where: Q = heat energy m = mass of the substance c = specific heat capacity of the substance ΔT = change in temperature In this case, m = 250 g, c = 4.18 J/g-K, and ΔT = 98°C - 22°C = 76°C. So, Q = 250 g * Show more…
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