Question

Consider a swinging pendulum with length l = 10 cm, a mass of 1 gm swinging at the end of it. Suppose that Planck's constant was 6.63 erg-sec instead of 6.63 x 10^-27 erg-sec. Calculate the minimum amplitude A (in cm) of the pendulum oscillation which would be allowed by Planck's quantum hypothesis not including A = 0. What is the second smallest allowed amplitude of oscillation? Hint: First calculate the frequency of a pendulum of length 10 cm. Then, for a pendulum with small angle oscillations, the total energy, E, potential plus kinetic, can be written as $E = \frac{1}{2}mg\frac{A^2}{l}$. Here, l is the length of the pendulum, m is the mass of the swinging object and g = 980 cm/sec^2 is the acceleration of gravity, and A is amplitude of the oscillation 3.5 cm and 7.2 cm 0.46 cm and 0.65 cm 0.001 cm and 0.0014 cm 0.45 cm and .90 cm 0.63 cm and 1.26 cm 0.0007 and 0.001 cm

          Consider a swinging pendulum with length l = 10 cm, a mass of 1 gm swinging at the end of it. Suppose that Planck's constant was 6.63 erg-sec instead of 6.63 x 10^-27 erg-sec. Calculate the minimum amplitude A (in cm) of the pendulum oscillation which would be allowed by Planck's quantum hypothesis not including A = 0. What is the second smallest allowed amplitude of oscillation? Hint: First calculate the frequency of a pendulum of length 10 cm. Then, for a pendulum with small angle oscillations, the total energy, E, potential plus kinetic, can be written as $E = \frac{1}{2}mg\frac{A^2}{l}$. Here, l is the length of the pendulum, m is the mass of the swinging object and g = 980 cm/sec^2 is the acceleration of gravity, and A is amplitude of the oscillation

3.5 cm and 7.2 cm
0.46 cm and 0.65 cm
0.001 cm and 0.0014 cm
0.45 cm and .90 cm
0.63 cm and 1.26 cm
0.0007 and 0.001 cm

Consider a swinging pendulum with length l = 10 cm, a mass of 1 gm swinging at the end of it. Suppose that Planck's constant was 6.63 erg-sec instead of 6.63 x 10^-27 erg-sec. Calculate the minimum amplitude A (in cm) of the pendulum oscillation which would be allowed by Planck's quantum hypothesis not including A = 0. What is the second smallest allowed amplitude of oscillation? Hint: First calculate the frequency of a pendulum of length 10 cm. Then, for a pendulum with small angle oscillations, the total energy, E, potential plus kinetic, can be written as E = (1)/(2)mg(A^2)/(l). Here, l is the length of the pendulum, m is the mass of the swinging object and g = 980 cm/sec^2 is the acceleration of gravity, and A is amplitude of the oscillation

3.5 cm and 7.2 cm
0.46 cm and 0.65 cm
0.001 cm and 0.0014 cm
0.45 cm and .90 cm
0.63 cm and 1.26 cm
0.0007 and 0.001 cm

Added by Allison A.

Question

Please give Ace some feedback