Question

When a 0.8 mm diameter tube is immersed in a liquid with a density of 820 kg/m$^3$, the liquid rises 7 mm in the tube and makes a contact angle of 26°. Which of the following is the surface tension of the liquid? ($g$=9.81 m/s$^2$) 0.025 Nm$^{-1}$ 0.025 Nm$^{-1}$ 0.25 Nm$^{-1}$ 0.25 Nm$^{-1}$

          When a 0.8 mm diameter tube is immersed in a liquid with a density of 820 kg/m$^3$, the liquid
rises 7 mm in the tube and makes a contact angle of 26°. Which of the following is the surface
tension of the liquid? ($g$=9.81 m/s$^2$)
0.025 Nm$^{-1}$
0.025 Nm$^{-1}$
0.25 Nm$^{-1}$
0.25 Nm$^{-1}$
        
Show more…
When a 0.8 mm diameter tube is immersed in a liquid with a density of 820 kg/m^3, the liquid
rises 7 mm in the tube and makes a contact angle of 26°. Which of the following is the surface
tension of the liquid? (g=9.81 m/s^2)
0.025 Nm^-1
0.025 Nm^-1
0.25 Nm^-1
0.25 Nm^-1

Added by Justin T.

Close

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
I am not sure if it is true. When a 0.8 mm diameter tube is immersed in a liquid with a density of 820 kg/m^3, the liquid rises 7 mm in the tube and makes a contact angle of 26°. Which of the following is the surface tension of the liquid? (g = 9.81 m/s^2) 1.02 N/m
Close icon
Play audio
Feedback
Powered by NumerAI
David Collins Jennifer Stoner
Ivan Kochetkov verified

Adi S and 71 other subject Chemistry 101 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
a-12-mm-diameter-tube-is-inserted-into-an-unknown-liquid-whose-density-is-960-kgm3-and-it-is-observed-that-the-liquid-rises-5-mm-in-the-tube-making-a-contact-angle-of-15-determine-the-surfac-74815

A 1.2-mm-diameter tube is inserted into an unknown liquid whose density is 960 kg/m3, and it is observed that the liquid rises 5 mm in the tube, making a contact angle of 15°. Determine the surface tension of the liquid.

Adi S.

a-16-mm-diameter-tube-is-inserted-into-an-unknown-liquid-whose-density-is-960-kgm3-and-it-is-observed-that-the-liquid-rises-5-mm-in-the-tube-making-a-contact-angle-of-15-determine-the-surfac-86061

A 1.6-mm-diameter tube is inserted into an unknown liquid whose density is 960 kg/m³, and it is observed that the liquid rises 5 mm in the tube, making a contact angle of 15°. Determine the surface tension of the liquid.

Eduard S.

when-a-2-mm-diameter-tube-is-inserted-into-a-liquid-in-an-open-tank-the-liquid-is-observed-to-rise-2

When a 2 -mm-diameter tube is inserted into a liquid in an open tank, the liquid is observed to rise $10 \mathrm{mm}$ above the free surface of the liquid (see Video $V 1.10$ ). The contact angle between the liquid and the tube is zero, and the specific weight of the liquid is $1.2 \times 10^{4} \mathrm{N} / \mathrm{m}^{3}$. Determine the value of the surface tension for this liquid.

Fundamentals of Fluid Mechanics


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,948 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,872 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,285 solutions

*

Transcript

-
00:01 For the given problem we have been given that the diameter is 1 .2 millimeter the density is given as 960 kilogram per meter cube also it has been given that the height is 5 millimeters the value of theta is given as 15 degrees so if we need to find the height we know the relation for height and the surface tension s that will be height will be equal to 2 times the surface tension cos theta divided upon ro g r so if we need to find the surface and so h will be equal to h row g r divided upon 2 cos theta so we can say that the value of radius is diameter upon 2 that will be because to 1 .2 divided upon 2 but it is amm so in meter it will be 10 to the power minus 3 meters and this will be equal to 0 .6 multiplied to 10 to the…
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever