Question

A more realistic problem: The Speeder still moves at a constant rate of 40 m/s while Car 1 is at the pit stop. And as soon as Car 2 reaches the pit stop, Car 1 begins to accelerate at the same rate of 2.0 m/s², but only until it reaches its maximum speed of 60 m/s, which she then maintains until catching Car 2. How much time passes before Car 2 is overtaken by Car 1? Correct answer: 45 s How far does Car 2 go before being overtaken by Car 1? Correct answer: 1800 m

          A more realistic problem:

The Speeder still moves at a constant rate of 40 m/s
while Car 1 is at the pit stop. And as soon as Car 2 reaches
the pit stop, Car 1 begins to accelerate at the same rate of 2.0 m/s²,
but only until it reaches its maximum speed of 60 m/s, which she then
maintains until catching Car 2.

How much time passes before Car 2 is overtaken by Car 1?
Correct answer: 45 s

How far does Car 2 go before being overtaken by Car 1?
Correct answer: 1800 m

A more realistic problem:

The Speeder still moves at a constant rate of 40 m/s
while Car 1 is at the pit stop. And as soon as Car 2 reaches
the pit stop, Car 1 begins to accelerate at the same rate of 2.0 m/s²,
but only until it reaches its maximum speed of 60 m/s, which she then
maintains until catching Car 2.

How much time passes before Car 2 is overtaken by Car 1?
Correct answer: 45 s

How far does Car 2 go before being overtaken by Car 1?
Correct answer: 1800 m

Added by Sumit C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

11/26/2021

Step 1

Given: Initial speed (u) = 0 m/s, final speed (v) = 60 m/s, acceleration (a) = 2 m/s^2 Using the first equation of motion: v = u + at 60 = 0 + 2t t = 30 seconds Show more…

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