00:01
Hello students, in this question we are going to find out the total heat that involved in increasing the temperature of the ice at minus 10 degree celsius to water at 59 degree celsius.
00:12
Whenever there is a phase change occur, the latent heat will plays its role.
00:16
Whenever there is an increase or decrease in the temperature occur, the specific heat plays the role.
00:21
So, here the specific heat and here will be the latent heat as ice is converted to water i .e.
00:27
Solid is converted to liquid and here the specific heat has been occur.
00:31
Let it be q1, q2 and q3.
00:35
The mass of the ice given here is equal to 930 g.
00:41
This will be equal to 0 .930 kg.
00:45
So, first of all we are going to find out the q1 i .e.
00:49
The specific heat which is given by mass into cp of ice into del t.
00:54
Substituting the known value, the mass is equal to 0 .930 and the cp of ice given in the question is equal to 2100 and the del t which is equal to 273 minus 263, this will be equal to 10.
01:10
On solving this, we will get the q1 value will be equal to 19 .530 kj...