Question

Figure 1 shows a polypropylene foam. At room temperature, the microstructure of the foam will fail via plastic deformation under compressive loading. Calculate the plateau stress of the foam using Equation (1). Assume the yield strength of PP is 32MPa and the foam has a relative density of 0.25. Give your answer in MPa correct to 1 decimal place.\\ $\frac{\bar{\sigma}_{pl}}{\sigma_{f,s}} = 0.3 \left(\frac{\bar{\rho}}{\rho_s}\right)^{3/2}$ Eq (1) Figure 1. Polypropylene foam. Answer:

          Figure 1 shows a polypropylene foam. At room temperature, the microstructure of the foam will fail via plastic deformation under compressive loading. Calculate the plateau stress of the foam using Equation (1). Assume the yield strength of PP is 32MPa and the foam has a relative density of 0.25. Give your answer in MPa correct to 1 decimal place.\\
$\frac{\bar{\sigma}_{pl}}{\sigma_{f,s}} = 0.3 \left(\frac{\bar{\rho}}{\rho_s}\right)^{3/2}$
Eq (1)
Figure 1. Polypropylene foam.
Answer:
        
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Figure 1 shows a polypropylene foam. At room temperature, the microstructure of the foam will fail via plastic deformation under compressive loading. Calculate the plateau stress of the foam using Equation (1). Assume the yield strength of PP is 32MPa and the foam has a relative density of 0.25. Give your answer in MPa correct to 1 decimal place.

(ĻƒĢ…pl)/(σf,s) = 0.3 ((ρ̅)/())^3/2
Eq (1)
Figure 1. Polypropylene foam.
Answer:

Added by Mariah S.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Figure 1 shows a polypropylene foam. At room temperature, the microstructure of the foam will fail via plastic deformation under compressive loading. Calculate the plateau stress of the foam using Equation 1. Assume the yield strength of PP is 32 MPa and the foam has a relative density of 0.25. Give your answer in MPa, correct to 1 decimal place. Equation 1: 3/2 * Opl = 0.3 * Eq1 * Of,s * Ps Figure 1. Polypropylene foam
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00:01 Hello students in the question we are given a hollow steel column and a solid column here we have formula pb it is equal to pi square ei divided by le square here we have pb it is directly proportional to moment of inertia we can write for solid rod divided by for hollow rod this is equal to is divided by ih here this is equal to pi by 64 into p to the power 4 divided by here we have pi by…
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