If there are 10 points on a plane, 4 of them are collinear and no other 3 points are collinear, how many lines are formed?
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This can be calculated using the combination formula, which is nC2 = n! / (2!(n-2)!), where n is the total number of points. In this case, n = 10, so the number of lines formed by choosing any 2 points is 10C2 = 10! / (2!(10-2)!) = 10! / (2!8!) = (10 * 9) / (2 * Show more…
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