00:01
Hi, given the equation of the plane as x is equal to p plus sv plus tw, then given over here x is equal to 1 3 2 plus s 4 minus 2 0 plus t 1 minus 1 1 and n vector as a b c is orthogonal to both v and w.
00:27
So, since it is orthogonal to v and w it must be v cross w.
00:32
Now, over here comparing this with this.
00:35
So, we have v as 4 minus 2 0 and we have w as 1 minus 1 and 1.
00:44
So, n vector will be v cross w that is i j k 4 minus 2 0 1 minus 1 1.
00:56
So, this is simply equal to minus 2 i cap minus 4 j cap minus 2 k cap.
01:01
So, n vector simply becomes 2 4 2.
01:06
So, the equation of the plane is 2 now x minus.
01:10
So, this is the passing point x minus 1 plus 4 y minus 3 plus 2 z minus 2 is equal to 0.
01:19
So, solving this we get 2 x plus 4 y plus 2 z is equal to 18.
01:28
Now, next we have the other way round.
01:31
So, we have v vector as 2 1 and over here we are taking x and w vector as 1 1 say y over here and they are both orthogonal to n vector as 3 minus 2 1.
01:51
So, again n vector must be v cross w.
01:54
So, that is i j k 2 1 1 1 x y...