If 14.57 mL of a N2S2O3 solution were required to titrate the iodine formed from 20.95 mL of a 0.0111 M KIO3 solution and excess KI, what would the molarity of the Na2S2O3 solution be?
Added by Lila H.
Step 1
First, we need to find the moles of KIO3 in the solution. We can do this using the formula: moles = molarity × volume (in liters). moles of KIO3 = 0.0111 M × 0.02095 L = 0.00023205 moles Show more…
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