Question

If a line ax + 2y = k forms a triangle of area 3 sq.units with the coordinate axis and is perpendicular to the line 2x - 3y + 7 = 0, then the product of all the possible values of k is

Name: if a line ax 2y k forms a triangle of area 3 squnits with the coordinate axis and is perpendicular to the line 2x 3y 7 0 then the product of all the possible values of k is 88295
Uploaded: 2022-07-05T00:38:19-08:00
Duration: 2 min 35 s
Channel: Gregory Higby
Description: if a line ax 2y k forms a triangle of area 3 squnits with the coordinate axis and is perpendicular to the line 2x 3y 7 0 then the product of all the possible values of k is 88295

          If a line ax + 2y = k forms a triangle of area 3 sq.units with the coordinate axis and is perpendicular to the line 2x - 3y + 7 = 0, then the product of all the possible values of k is

Added by Laura O.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Gregory Higby

07/05/2022

Step 1

To find its slope, we rewrite it in slope-intercept form (y = mx + b), where m is the slope. \[ 2x - 3y + 7 = 0 \implies -3y = -2x - 7 \implies y = \frac{2}{3}x + \frac{7}{3} \] The slope of this line is \( m_1 = \frac{2}{3} \). Show more…

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If a line ax + 2y = k forms a triangle of area 3 sq.units with the coordinate axis and is perpendicular to the line 2x - 3y + 7 = 0, then the product of all the possible values of k is