0:00
Hello everyone.
00:01
In this question, it is given that there is a two circle with different radii having quads ab and cd such that they have given ab is congruent to cd.
00:09
So, we have to prove the arcs inserted by intersected by this code are also congruent.
00:15
So, let us see proof for this.
00:17
First, we want to draw the diagram of the scenario.
00:21
So, i have drawn the diagram that is this is the circle with center o and a quad ab and this is the circle with center o dash and a quad cd and there is the angle theta and here is the angle alpha.
00:34
So, since op is perpendicular to ab and o dash q perpendicular to cd and ab is congruent to cd which is given in the question.
00:47
So, this implies p and q are midpoints of ab and cd respectively.
01:00
So, since it is the midpoint, we can write pb as 1 by 2 ab.
01:08
Since it is congruent, we can write 1 by 2 cd.
01:12
1 by 2 cd is nothing but qd.
01:17
So, let ob is greater than o dash t.
01:25
Then, we have sine theta that is opposite by hypotenuse pb by ob and for this triangle, we have sine alpha that is qd by o dash t.
01:40
Already, we know qd can be written as pb...