If $\cos(\theta) = \frac{2}{9}$ and $\theta$ is in the 1st quadrant, find the exact value for $\sin(\theta)$.\n$\sin(\theta) = $
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Since we are given that cos(0) and 0 is in the 1st quadrant, we can use the Pythagorean identity: sin^2(0) + cos^2(0) = 1 We are asked to find sin(0), so we can rearrange the equation to solve for sin(0): sin^2(0) = 1 - cos^2(0) Now, we can take the square Show more…
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