00:02
Hello everyone, it is given in the question that a table is there, right? and over a table, a chain is put in such a way that some part of changing hanging, right? it is also given in the question that as soon as the hanging part becomes one third of the total length, then it starts sliding.
00:28
It means our part is 2 l by 3, right? to find the coefficient of static friction between the table and the.
00:39
So coming to the solution part, let us assume that total mass is equal to and length is here l right.
00:54
So mass per unit length, this is equal to m upon l right.
01:07
Now we can write that fs max, this is static friction that is acting, that is equal to m into g here small m is the mass of the hanging part so this will be equal to m by l into l by three right now g will be g fs max we can write mu s multiplied by the part which is applying normal on the table so this will be equal to m by l multiplied by 2 l by 3 into g since g, g will cancel out m, l, and f...