2 Given that the binomial expansion of $(1 + kx)^{-4}$, $|kx| < 1$, is $1 - 6x + Ax^2 + ...$ (a) find the value of the constant $k$, (b) find the value of the constant $A$, giving your answer in its simplest form.
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The binomial theorem states that for any real numbers a and b, and any positive integer n, the expansion of (a + b)^n can be written as: (a + b)^n = C(n, 0) * a^n * b^0 + C(n, 1) * a^(n-1) * b^1 + C(n, 2) * a^(n-2) * b^2 + ... + C(n, n-1) * a^1 * b^(n-1) + C(n, Show more…
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