In a study of how well bears are doing at yellowstone...

Name: in a study of how well bears are doing at yellowstone national park head widths and weights of 14 randomly selected bears at that park are collected a correlation coefficient of 0721 is obta 27673
Uploaded: 2022-04-20T15:22:15-08:00
Duration: 3 min 25 s
Channel: David Nguyen
Description: in a study of how well bears are doing at yellowstone national park head widths and weights of 14 randomly selected bears at that park are collected a correlation coefficient of 0721 is obta 27673

In a study of how well bears are doing at Yellowstone National Park, head widths and weights of 14 randomly selected bears at that park are collected. A correlation coefficient of 0.721 is obtained, along with the following regression equation: 𝑦ොൌെ212 ൅ 61.9𝑥 where 𝑦ො is the best predicted weight for a bear (measured in pounds) with a head width of x inches. 14. What is the population and sample here in this study? 15. Is there enough evidence of a linear association between head width and weights of bears at this national park? Explain why or why not. 16. What is the head width of a bear who weighs 250 pounds? Round your final answer off to the nearest hundredth of an inc

Transcript

00:01 Hi, i'm david and i'm here to help you answer your question.

00:03 Now let me bring up your question here.

00:06 In the question here, we are going to discuss about the correlation coefficient and the coefficient on the determination.

00:15 Now let me remind you that we will have the r stands for the correlation of correlation coefficient.

00:29 And here it has a value between the minus 1 and the 1.

00:33 And the second one will be the r square it will be called the coefficient of determination and the value of the r square will be always between the 1 and the 0 now the meaning of the coefficient of the determination it will be it will explain the variation in the dependent variable and here here in this question we are given several choices and here there's some missing information before that even though in this question if we pay attention to the two values first this will be this one and the second one be this we see that we can identify that the r square it will equal to the smallest value will be the z -pon -nine 47 and the r here it will be the bigger one because when we turn the square root of the 0 .947 get equal to the 0 .973 so this tells us that doesn't explain that the 94 .7 % of the variability in the peers weight so therefore from here we will try to eliminate the wrong option.

02:22 The first one says that we will have the 97 .3 % of the variability of the base weight can be accounted.

02:31 So this one will be wrong.

02:32 It is supposed to be the 94 .7%.

02:35 And the next one, the correction is the 0 .94...

Question

Please give Ace some feedback