Question

In order to augment the rate of cooling of a device, a pin fin of 2.5mm diameter is attached to its casting. The wall of the casting has a temperature of 95°C, whereas it has a temperature difference of 70°C with the surrounding air. Primarily, the heat transfer occurs through natural convection with a convection coefficient of 10 W/m^2.°C. 1) What is the heat loss if the fin is infinitely long? 2) What is the heat loss if the fin is 25mm long and convection process at 113°C occurs with the same convection coefficient as described earlier? 3) How long should the fin be to justify the assumption of its infinite length with a 5% error margin?

          In order to augment the rate of cooling of a device, a pin fin of 2.5mm diameter is attached to its casting. The wall of the casting has a temperature of 95°C, whereas it has a temperature difference of 70°C with the surrounding air. Primarily, the heat transfer occurs through natural convection with a convection coefficient of 10 W/m^2.°C.

1) What is the heat loss if the fin is infinitely long?
2) What is the heat loss if the fin is 25mm long and convection process at 113°C occurs with the same convection coefficient as described earlier?
3) How long should the fin be to justify the assumption of its infinite length with a 5% error margin?
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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In order to augment the rate of cooling of a device, a pin fin of 2.5mm diameter is attached to its casting. The wall of the casting has a temperature of 95°C, whereas it has a temperature difference of 70°C with the surrounding air. Primarily, the heat transfer occurs through natural convection with a convection coefficient of 10 W/m^2.°C. 1) What is the heat loss if the fin is infinitely long? 2) What is the heat loss if the fin is 25mm long and convection process at 113°C occurs with the same convection coefficient as described earlier? 3) How long should the fin be to justify the assumption of its infinite length with a 5% error margin?
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Transcript

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00:01 The adiabatic tip theta upon theta b is equal to e to the power minus m x.
00:10 Therefore, m is equal to under root h p upon k a c or under root 4 h upon k d.
00:22 So, under root 4 into 5 upon 4 into 8 into 10 to the power minus 2.
00:30 Therefore, m is 7 .905...
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