Question

In order to conduct a hypothesis test for the population proportion, you sample 325 observations that result in 117 successes. (You may find it useful to reference the appropriate table: z table or ttable) $H_0: p \ge 0.41; H_a: p < 0.41$. a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round final answer to 2 decimal places.) Test statistic a-2. Find the $p$-value. $ \bigcirc p \text{-value} < 0.01 $ $ \bigcirc 0.01 \le p \text{-value} < 0.025 $ $ \bigcirc 0.025 \le p \text{-value} < 0.05 $ $ \bigcirc 0.05 \le p \text{-value} < 0.10 $ $ \bigcirc p \text{-value} \ge 0.10 $ a-3. At the 0.01 significance level, What is the conclusion? $ \bigcirc \text{Do not reject } H_0 \text{ since the } p \text{-value is smaller than significance level.} $ $ \bigcirc \text{Do not reject } H_0 \text{ since the } p \text{-value is greater than significance level.} $ $ \bigcirc \text{Reject } H_0 \text{ since the } p \text{-value is smaller than significance level.} $ $ \bigcirc \text{Reject } H_0 \text{ since the } p \text{-value is greater than significance level.} $

          In order to conduct a hypothesis test for the population proportion, you sample 325 observations that result in 117 successes. (You may find it useful to reference the appropriate table: z table or ttable)
$H_0: p \ge 0.41; H_a: p < 0.41$.
a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round final answer to 2 decimal places.)
Test statistic
a-2. Find the $p$-value.
$ \bigcirc p \text{-value} < 0.01 $
$ \bigcirc 0.01 \le p \text{-value} < 0.025 $
$ \bigcirc 0.025 \le p \text{-value} < 0.05 $
$ \bigcirc 0.05 \le p \text{-value} < 0.10 $
$ \bigcirc p \text{-value} \ge 0.10 $
a-3. At the 0.01 significance level, What is the conclusion?
$ \bigcirc \text{Do not reject } H_0 \text{ since the } p \text{-value is smaller than significance level.} $
$ \bigcirc \text{Do not reject } H_0 \text{ since the } p \text{-value is greater than significance level.} $
$ \bigcirc \text{Reject } H_0 \text{ since the } p \text{-value is smaller than significance level.} $
$ \bigcirc \text{Reject } H_0 \text{ since the } p \text{-value is greater than significance level.} $

In order to conduct a hypothesis test for the population proportion, you sample 325 observations that result in 117 successes. (You may find it useful to reference the appropriate table: z table or ttable)
H0: p ≥ 0.41; Ha: p < 0.41.
a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round final answer to 2 decimal places.)
Test statistic
a-2. Find the p-value.
◯ p -value < 0.01
◯ 0.01 ≤ p -value < 0.025
◯ 0.025 ≤ p -value < 0.05
◯ 0.05 ≤ p -value < 0.10
◯ p -value≥ 0.10
a-3. At the 0.01 significance level, What is the conclusion?
◯Do not reject H0 since the p -value is smaller than significance level.
◯Do not reject H0 since the p -value is greater than significance level.
◯Reject H0 since the p -value is smaller than significance level.
◯Reject H0 since the p -value is greater than significance level.

Added by Kayla M.

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