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In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a further step to isolate it. Let's say we now have * $$3C + 4D = 5$$ * $$2C + 5D = 2$$ None of these terms has a coefficient of 1. Instead, we'll pick the variable with the smallest coefficient and isolate it. Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. Which of the following expressions would result from that process? $$D = \frac{2}{5} - \frac{2}{5}C$$ $$C = \frac{5}{3} - \frac{4}{3}D$$ $$C = 1 - \frac{5}{2}D$$ $$D = \frac{5}{4} - \frac{3}{4}C$$ Submit Request Answer

Name: in some cases neither of the two equations in the system will contain a variable with a coefficient of 1 so we must take a further step to isolate it lets say we now have 3c 4d 5 2c 5d 2 non 43643
Uploaded: 2023-01-24T19:10:29-08:00
Duration: 2 min 15 s
Channel: Maria Dearborn
Description: in some cases neither of the two equations in the system will contain a variable with a coefficient of 1 so we must take a further step to isolate it lets say we now have 3c 4d 5 2c 5d 2 non 43643

          In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a further step to isolate it. Let's say we now have
* $$3C + 4D = 5$$
* $$2C + 5D = 2$$
None of these terms has a coefficient of 1. Instead, we'll pick the variable with the smallest coefficient and isolate it. Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. Which of the following expressions would result from that process?
$$D = \frac{2}{5} - \frac{2}{5}C$$
$$C = \frac{5}{3} - \frac{4}{3}D$$
$$C = 1 - \frac{5}{2}D$$
$$D = \frac{5}{4} - \frac{3}{4}C$$
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in some cases neither of the two equations in the system will contain a variable with a coefficient of 1 so we must take a further step to isolate it lets say we now have 3c 4d 5 2c 5d 2 non 43643

Added by Trinidad C.

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