In the figure a potential difference V = 100 V is applied...

In the figure a potential difference V = 100 V is applied across a capacitor arrangement with capacitances C? = 9.06 µF, C? = 5.24 µF, and C? = 4.07 µF. What are (a) charge q?, (b) potential difference V?, and (c) stored energy U? for capacitor 3, (d) q?, (e) V?, and (f) U? for capacitor 1, and (g) q?, (h) V?, and (i) U? for capacitor 2?

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00:01 Hi in this question it is given that c1 is equal to c6 which is 4 mu f which is 4 into 10 to power minus 6 f in the same way c3 is equal to c5 which is 2 .5 c2 which is 2 .5 c4 which is 4 into 10 to power minus 6f now the voltage of a battery v is 15 volt where c5 and c3 are connected in series so the result of c5 and c3 which is denoted by equation 1 by c is equal to 1 divided by c3 plus 1 divided by c5 which is 4 into 10 to power minus 6 into 4 into 10 to power minus 6 divided by 4 into 10 to power minus 6 plus 4 into 10 to power minus 6 does give us 2 mu f r c is equal to 2 into 10 to power minus 6 6f where c6 and c1 are connected in parallel so the resultant of c6 and c1 which is denoted by c dash is equal to c6 plus c1 which is 4 plus 4 that is 8 mu f or 8 into 10 10 to power minus 6 f now c4 c and c2 are connected in parallel thus the resultant is given by c double dash which is c4 plus c2 which is 22 muf which is 22 into 10 to power minus 6f further now the c double dash and c dash are connected in series so the resultant of c double dash and c dash is given by 1 divided by c equivalent is equal to 1 divided by c double dash plus 1 divided by c double dash plus 1 divided by c which is 22 into 8 divided by 22 plus 8 which is 5 .86 muf so the part a of the question where the equivalent capacitance c eq is 5 .86 muf b where the chart stored by the c equivalent which is q is equal to c equivalent dot v which is 5 .86 into 15 that is 88 .00 muc part c of the question where v1 is equal to v6 which is equal to q divided by c which is 88 divided by 8 that is 11 volt thus we get v1 as 11 volt in part d where q1 of a capacitor 1 which is q1 is equal to c1 b1 which is 4 into 11 which is 44 muci thus q1 is equal to 44 mu c now in the part e where v2 is equal to v4 which is v minus v6 thus v2 is equal to v4 which is 15 minus 11 that is 4 volt further in the part f where q2 is equal to c2 v2 which is 4 into 10 which is 40 mu c pt.

04:35 Part g where v3 is equal to v4 divided by 2 that is 4 divided by 2 which is 2 volt and finally in part h where q3 is equal to c3 v3 that is 4 into 2 does we get q3 as 8 mu c...

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