Question

In the last municipal election, $62\frac{1}{2}\%$ of the population of 94,800 was eligible to vote. Of those eligible, $33\frac{1}{3}\%$ voted. (a) What was the number of eligible voters? (b) How many voted? (a) The number of eligible voters was (Simplify your answer.) Clear all Check answer

Name: in the last municipal election 62frac12 of the population of 94800 was eligible to vote of those eligible 33frac13 voted a what was the number of eligible voters b how many voted a the numbe 01116
Uploaded: 2023-03-31T19:55:54-08:00
Duration: 1 min 36 s
Channel: Sri K
Description: in the last municipal election 62frac12 of the population of 94800 was eligible to vote of those eligible 33frac13 voted a what was the number of eligible voters b how many voted a the numbe 01116

          In the last municipal election, $62\frac{1}{2}\%$ of the population of 94,800 was eligible to vote. Of those eligible, $33\frac{1}{3}\%$ voted.
(a) What was the number of eligible voters?
(b) How many voted?
(a) The number of eligible voters was
(Simplify your answer.)
Clear all
Check answer

$in the last municipal election 62frac12 of the population of 94800 was eligible to vote of those eligible 33frac13 voted a what was the number of eligible voters b how many voted a the numbe 01116$

Added by Nicholas S.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Sri K

03/31/2023

Step 1

The total population is 94,800. The percentage of the population eligible to vote is $62\frac{1}{2}\%$. First, convert the mixed percentage to a fraction or decimal. $62\frac{1}{2}\% = 62.5\% = \frac{62.5}{100} = 0.625$. Number of eligible voters = $0.625 \times Show more…

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In the last municipal election, $62\frac{1}{2}\%$ of the population of 94,800 was eligible to vote. Of those eligible, $33\frac{1}{3}\%$ voted. (a) What was the number of eligible voters? (b) How many voted? (a) The number of eligible voters was (Simplify your answer.) Clear all Check answer