A capacitor $C = 10 \mu F$ with an initial charge 4.0 mC is connected to an ideal inductor $L = 0.30 H$. What is the peak current in the inductor?
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We can use the formula V = L * di/dt, where V is the voltage across the inductor, L is the inductance, and di/dt is the rate of change of current. Since the inductor is connected to an ideal capacitor, the current through the inductor will be changing at a Show more…
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