00:01
Okay, so here we know that the mean cost of buying stuff at the grocery store for a certain meal is $13 .4.
00:08
We take a sample of 100 restaurants, and it has a standard deviation, or sorry, a mean for the sample of 1275, and a standard deviation s of 2 for the restaurant meal.
00:26
So first of all the hypotheses that we're going to have, the hypotheses, by the way, are going to have.
00:32
Going to be the same whether we use the p -value approach or the critical value approach.
00:37
The null hypothesis is always going to be that the mean is equal to a certain value.
00:44
Okay, the claim.
00:45
And the alternative is going to be, we want to know which is cheaper.
00:51
It doesn't say, well, let's see, we're trying to support the conclusion that the mean cost of a restaurant meal is less than fixing a meal at home.
00:59
Okay, so we want less than on our alternative hypothesis there.
01:08
So we're going to get our test statistic.
01:10
It's going to be a t, and it's going to be x bar minus the mean from the null hypothesis over s over the squared event.
01:17
So that's 12 .75 minus 13 .4, 13 .04 over 2 over the square of 100.
01:28
So let's go ahead and put that into a calculator.
01:31
So 12 .75 minus 13 .04 gives us negative .29.
01:38
And then divide by in parentheses 2 over the square root of 100 gives us for our test statistic negative 1 .45...