InputStream in = new FileInputStream(...); try { System.out.print("A"); // code that could cause an exception System.out.print("B"); } catch (IOException e) { System.out.print("C"); } finally { in.close(); System.out.print("D"); } System.out.println("E"); What will be the string print in output if the try blocks throws a FileNotFoundException exception? ACDE ABDE ABCDE ACD

          InputStream in = new FileInputStream(...);
try {
System.out.print("A");
// code that could cause an exception
System.out.print("B");
} catch (IOException e) {
System.out.print("C");
} finally {
in.close();
System.out.print("D");
}
System.out.println("E");
What will be the string print in output if the try blocks throws a FileNotFoundException exception?
ACDE
ABDE
ABCDE
ACD

InputStream in = new FileInputStream(...);
try
System.out.print("A");
// code that could cause an exception
System.out.print("B");
catch (IOException e)
System.out.print("C");
finally
in.close();
System.out.print("D");

System.out.println("E");
What will be the string print in output if the try blocks throws a FileNotFoundException exception?
ACDE
ABDE
ABCDE
ACD

Added by Sarah C.

C# Programming: From Problem Analysis to Program Design

Barbara Doyle 3rd Edition

Chapter 13

Instant Answer

Solved by Expert Syed Vasi

Step 1

The code starts by creating an InputStream object called "in" using the FileInputStream class. Show more…

Show all steps

Thanks for your feedback!

InputStream in = new FileInputStream(...); try { System.out.print("A"); // code that could cause an exception System.out.print("B"); } catch (IOException e) { System.out.print("C"); } finally { in.close(); System.out.print("D"); } System.out.println("E");