00:01
Okay, this is the continuous compound, so i'm going to do the second row.
00:08
Initial y naught is 8000, so...
00:12
And it becomes 9125 .50 8000 e to the 5k, sulfur.
00:24
So, k is 0 .026 or 2 .6%, okay? and then the doubling time is ln of 2 divided by k, which is...
00:46
The doubling time is about 27 years, it's 26 .9, but...
00:51
So that's the second row.
00:54
Third row we have...
00:56
Interest rate is given, so amount after 5 years is 1141471.
01:07
We don't know initial amount.
01:09
E to the 0 .084 and 5 years, so from here we're going to solve the initial amount.
01:18
So initial amount is 7500, okay? once again, t double is ln of 2 divided by 0 ....
01:34
Well, it's actually 8 .4, you just write there...