Question

K. Find f(x) and g(x) such that h(x) = (f ∘ g)(x). h(x) = √√(1 - √√(x - 1)) A. f(x) = √√(x - 1), g(x) = √(1 - x) B. f(x) = √(1 - x), g(x) = √(x - 1) C. f(x) = √(x - 1), g(x) = √(x - 1) D. f(x) = √√√(1 + x), g(x) = √(x - 1)

          K. Find f(x) and g(x) such that h(x) = (f ∘ g)(x). h(x) = √√(1 - √√(x - 1))

A. f(x) = √√(x - 1), g(x) = √(1 - x)
B. f(x) = √(1 - x), g(x) = √(x - 1)
C. f(x) = √(x - 1), g(x) = √(x - 1)
D. f(x) = √√√(1 + x), g(x) = √(x - 1)
        

Added by Jeffrey D.

Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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K. Find f(x) and g(x) such that h(x) = (f ∘ g)(x). h(x) = √√(1 - √√(x - 1)) A. f(x) = √√(x - 1), g(x) = √(1 - x) B. f(x) = √(1 - x), g(x) = √(x - 1) C. f(x) = √(x - 1), g(x) = √(x - 1) D. f(x) = √√√(1 + x), g(x) = √(x - 1)
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Transcript

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00:03 Hello, friends, welcome.
00:05 We have a question here and this is a homologous differentiation differential equation.
00:30 So here, our first equation is y square plus y x to d x is equal to, i'm sorry, this is added by x squared d, d, y is equal to 0.
00:51 Have to depreciate this equation.
00:54 So let's start solving.
00:56 This is a solve by the x squared d .y will be equal to minus y square plus y x, bx, and we y, upon bx be equal to minus y square plus y x by x squared...
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