Question

Let $\mu_1$ and $\mu_2$ denote true average densities for two different types of brick. Assuming normality of the two density distributions, test $H_0: \mu_1 - \mu_2 = 0$ versus $H_a: \mu_1 - \mu_2 \neq 0$ using the following data: $m = 7$, $\bar{x} = 22.79$, $s_1 = 0.161$, $n = 5$, $\bar{y} = 20.95$, and $s_2 = 0.250$. Calculate the test statistic and determine the $P$-value. (Round your test statistic to one decimal place and your $P$-value to three decimal places.) t = $P$-value = 0 State the conclusion in the problem context. (Use $\alpha = 0.05$.)

          Let $\mu_1$ and $\mu_2$ denote true average densities for two different types of brick. Assuming normality of the two density distributions, test $H_0: \mu_1 - \mu_2 = 0$ versus $H_a: \mu_1 - \mu_2 \neq 0$ using the following data: $m = 7$,
$\bar{x} = 22.79$, $s_1 = 0.161$, $n = 5$, $\bar{y} = 20.95$, and $s_2 = 0.250$.

Calculate the test statistic and determine the $P$-value. (Round your test statistic to one decimal place and your $P$-value to three decimal places.)

t = 
$P$-value = 0

State the conclusion in the problem context. (Use $\alpha = 0.05$.)

Let μ1 and μ2 denote true average densities for two different types of brick. Assuming normality of the two density distributions, test H0: μ1 - μ2 = 0 versus Ha: μ1 - μ2 ≠ 0 using the following data: m = 7,
x̅ = 22.79, s1 = 0.161, n = 5, y̅ = 20.95, and s2 = 0.250.

Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.)

t =
P-value = 0

State the conclusion in the problem context. (Use α = 0.05.)

Added by Sharon G.

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